Mary Jane Allen 
Mary Jane was born on July 31st, 1848 in Claiborne,Louisana. Mary Jane's father was Hiram George Allen and her mother is Mary Ann Daubin. Her paternal grandparents were John Calhoun Allen and Mary Holcombe. She had two brothers and a sister, named Hiram Andrew, Thomas Price and Angelina Rebecca Elizabeth. She was the oldest of the four children. She died at the age of 80 on July 18th, 1929 in Lufkin,Angelina Co..-
Ancestor Pedigree Chart
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- b.1752 in Ireland d.18 Aug 1813 in Spanish Territory of Tejas,Near San Antonio,Texas
- b.1774 in Campbell Co.,Kentucky d.1813 in Louisana
- b.1752 d.Jul 1803 in Campbell Co.,Ky.
- b.1795 in Campbell,Kentucky d.1867 in Lufkin,Angelina Co.,Texas
- b. in Campbell Co.,Kentucky
- b.1823 in Claiborne,Louisana d.07 Apr 1867 in Alexandria,Louisana
- b.1802 in Kentucky d.Jul 1869 in Lufkin,Angelina Co.,Texas
- b.31 Jul 1848 in Claiborne,Louisana d.18 Jul 1929 in Lufkin,Angelina Co.
- b.1831 in Mossouri
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‌Mary Jane and Martin VanBuren were married in a religious ceremony on October 31st, 1866.
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