Howard Allbee 
Howard was born on August 20th, 1802 in Danby, Rutland, VT, USA.1 Howard's father was Benjamin Albee and his mother was Abigail Thompson. His paternal grandparents were Ebenezer Allbee and Rachel Avery. He had four brothers and three sisters, named Jehiel Allbee, Adolphus, Benjamin, Enoch, Rachel, Clarissa and Diantha. He was the fourth youngest of the eight children. He had three half-brothers and three half-sisters, named Joseph, Amos, Luther Thompson, Miriam Allbee, Betsey Miranda and Sarah Jane. He died at the age of 77 on May 25th, 1880 in Albee, Saginaw, MI, USA.1 -
Ancestor Pedigree Chart
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- b.09 Jun 1743 in Townsend, Middlesex, MA, USA d.08 Aug 1818 in Rockingham, Windham, VT, USA
- b.1771 in Rockingham, Windham, VT, USA d.30 Dec 1858 in Concord, Erie, NY, USA
- b.15 Jul 1746 in Townsend, Middlesex, MA, USA d.04 Nov 1815 in Rockingham, Windham, VT, USA
- b.20 Aug 1802 in Danby, Rutland, VT, USA d.25 May 1880 in Albee, Saginaw, MI, USA
- b.1775 in MA, USA d.Nov 1861 in Collins, Erie, NY, USA
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