Mary E. ALTHERR 
Mary E. was born in November 1894 in , Lawrence, Ohio, USA.1 Mary E.'s father was Frank ALTHERR and her mother was Sophia. She had seven brothers and three sisters, named Frank J., Fredric, Victor, Anden F., John J., Albert N., Henry N., Evelyn, Florence and Jessie M.. She was the youngest of the eleven children.General Notes
SOURCE: 1900 Census - Elizabeth Twp., , Lawrence, Ohio - ED 66, Page 8A (50), Line 9, Visit 125, Image 15 on ancestry.com (9 June 1900)
ALTHER, Frank, Head, W, M, July 1846, 53, Marr 33 yrs, Germany, Germany,
, Sophia T., Wife, W, F, June 1850, 49, Marr 33 yrs, 12 children, 11 living, OH, Germany,
, Florence T., Daughter, W, F, Dec 1882, 17, Sgl, OH, Ger, OH
, Albert N. Son, W, M, Feb 1885, 15, OH, Ger, OH
, Jessie M., Daughter, W, F, Sept 1887, 12, OH, Ger, OH
, Henry N., Son, W, M, Oct 1890, 9, OH, Ger, OH
, Mary E., Daughter, W, F, Nov 1894, 5, OH, Ger, OH
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1 1900 Census - Elizabeth Twp., , Lawrence, Ohio - ED 66, Page 8A (50), Line 9, Visit 125, Image 15 on ancestry.com (9 June 1900)
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